Given A-B = 3, B + C = - 5, then the value of the algebraic expression AC BC + A2 AB is () A. -15B. -2C. -6D. 6

RELATED INFORMATIONS

• 1. Given ABC = 1, a + B + C = 2, A2 + B2 + C2 = 3, find the sum of (AB + C-1), (BC + A-1), (AC + B-1) A2 + B2 + C2 = 3, 2 after a, B, C is the square,
• 2. Given that a, B and C are three sides of triangle, and a 2 + B 2 + C 2 + AB + AC + BC, the values of a, B and C are obtained
• 3. Let a, B, C be any integer which is not completely equal, if x = A2 BC, y = B2 AC, z = C2 ab
• 4. Let A.B.C be any real number which is not completely equal, if x = a-bc, y = b-ac, z = c-ab, Z, then x, y and Z are all less than 0 and no more than 0, then Connect. C at least one ＜ 0, D at least one ＞ 0
• 5. Let ABC be non-zero real numbers which are not equal to each other, and prove three equations It is impossible to prove that three equations ax ^ 2 + 2bx + C = 0, BX ^ 2 + 2cx + a = 0, CX ^ 2 + 2aX + B = 0 have two equal real roots
• 6. Given that ABC is a real number with complementary equality, we prove that a ^ 4 + B ^ 4 + C ^ 4 > ABC (a + B + C)
• 7. If ABC is a real number, a ^ 2 + B ^ 2 = 7, B ^ 2 + C ^ 2 = 8, C ^ 2 + A ^ 2 = 9, then the minimum value of AB + BC + AC is
• 8. Given that a plus B equals 3, B plus C equals 2, a plus C equals 5, find a square plus b square plus C square plus AB plus AC plus BC
• 9. It is known that the three sides of a triangle are a, B and C respectively, and the square of a + the square of B + the square of C equals AB + AC + BC, Please guess what shape this triangle is and explain your reason Thank you for your help!!!!!!!!! I'm in a hurry
• 10. If the three sides of a triangle A.B.C satisfy that the square of a plus the square of B plus the square of C equals AB plus AC plus BC, try to determine the shape of the triangle
• 11. Given A-B = - 2, B-C = 5, find the value of a ^ 2 + B ^ 2 + C ^ 2-ab-ac-bc
• 12. Given A-B = 3, B-C = - 1, find the value of a ^ 2 + B ^ 2 + C ^ 2-ab-bc-ac
• 13. It is known that: AB / (a + b) = 1, BC / (B + C) = 2, AC / (a + C) = 3
• 14. In the triangle ABC, ∠ C = 90 degrees, a = 1. B = 3, find C. in the triangle ABC, ∠ C = 90 degrees, ab = 3. AC = 2. 5, find BC 3. The two sides of the right triangle are a = 5. B = 12. Ask the third side C! Heroes, come and help! The answer will be given tonight! Seek detailed answer!! thank you very much!!
• 15. In the RT triangle ABC, ∠ C = 90 degrees, AC + BC = 7 / 2, ab-bc = 1 / 2. Find the length of ab
• 16. For a RT triangle ABC, ∠ B is 90 °, BC is 8 m long, AB and AC are 1.6 m long, the length of AB is calculated I'll give you more points if you get it right!
• 17. In RT △ ABC, angle c = 90 degrees, angle a = 50 degrees, ab = 5, find the length of BC and AC
• 18. Compare the size of a * + b * + C * and ab + BC + AC. * = 2
• 19. A ^ 2 + B ^ 2 + C ^ 2-ab-bc-ac = 0, the size relationship of ABC ABC is all positive
• 20. The square of ab-b-bc + AC Factorization