Given that a, B and C are three sides of triangle, and a 2 + B 2 + C 2 + AB + AC + BC, the values of a, B and C are obtained

Your question is wrong. It should be a ^ 2 + B ^ 2 + C ^ 2-ab-ac-bc = 0. Otherwise, it is impossible to prove that three sides a = b = C are equal
(a+b)^2-2ab+(b+c)^2-2bc+(c+a)^2-2ca=2(ab+ac+bc)
(a-b)^2+(b-c)^2+(c-a)^2=o
So a = b = C, the three sides are equal

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