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你的題目估計不對,應該是a^2+b^2+c^2-ab-ac-bc=0,否則沒法證明三條邊a=b=c相等. (a+b)^2-2ab+(b+c)^2-2bc+(c+a)^2-2ca=2(ab+ac+bc) (a-b)^2+(b-c)^2+(c-a)^2=o 所以a=b=c,三條邊相等
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