If the chord AB length of the left focus F1 passing through the hyperbola x216 − Y29 = 1 is 6, then the perimeter of △ abf2 (F2 is the right focus) is 6______ ．

From the standard equation of hyperbola x216 − Y29 = 1, we can get a = 4. From the definition of hyperbola, we can get: af2-af1 = 2A, BF2 - BF1 = 2A, ｜ af2 + BF2 - AB = 4A = 16, that is af2 + BF2 - 6 = 16, af2 + BF2 = 22. The perimeter of △ abf2 (F2 is the right focus) is: (AF1 + af2 & nbsp;) + (BF1 + BF2)

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