If vector a (1,2) B (4,3) C (- 2,5), then what is the shape of triangle ABC, if it is changed to B (2,2)

You can use the distance formula between two points
Find the distance between ab = 10 ^ 0.5
AC=3*2^0.5
BC=3*2^0.5
As you can see, AC = BC is an isosceles triangle
In addition, AC ^ 2 + BC ^ 2 = 36, AB ^ 2 = 10, there is no right angle in it, otherwise the sum of the squares of the two right angle sides is equal to the square of the third side
And so on, okay?

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