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你可以根據兩點間距離公式 求AB間距離=10^0.5 AC=3*2^0.5 BC=3*2^0.5 可以看出來,AC=BC,是等腰三角形 另外AC^2+BC^2=36,AB^2=10,沒有直角在裡面,否則兩個直角邊的平方和等於第三邊的平方 依此類推吧,懂了吧?
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