The object is in equilibrium under the action of three common forces. If we know that F1 and F2 are perpendicular, and the angle between F2 and F3 is 120 degrees, then the ratio of the three forces? The object is in equilibrium under the action of three common forces, as shown in Fig. 1-3-10. It is known that F1 and F2 are perpendicular, and the included angle between F2 and F3 is 120 degrees. Then the ratio of the magnitude of the three forces F1 ∶ F2 ∶ F3 is? Please explain, thank you!

The object is in equilibrium under the action of three common forces. If we know that F1 and F2 are perpendicular, and the angle between F2 and F3 is 120 degrees, then the ratio of the three forces? The object is in equilibrium under the action of three common forces, as shown in Fig. 1-3-10. It is known that F1 and F2 are perpendicular, and the included angle between F2 and F3 is 120 degrees. Then the ratio of the magnitude of the three forces F1 ∶ F2 ∶ F3 is? Please explain, thank you!

Let the resultant force of F1 and F2 be F4, then the angle between F4 and F2 is 60 degrees. According to the Pythagorean theorem of f1.f2.f4, we can get that F1: F2: F3 = radical 3:1:2