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An object is subjected to three common forces F1, F2 and F3, and their resultant force is zero. The magnitude of these three forces is 10N, 20n and 30n respectively. Now, F2 suddenly decreases to 16N. If the direction of the three forces remains unchanged, what is the resultant force at this time? And this question There are three common forces F1, F2 and F3 in the horizontal direction, of which F1 is 20n in the west, F2 is 50N in the East and F3 is 40n in the south. The resultant force of these three forces can be obtained by drawing method
1. The resultant force of F1, F2 and F3 is zero, which means that the resultant force of F1, F3 and F2 are equal in size and opposite in direction, right? Now F2 suddenly decreases to 16N, but F1, F3 remains unchanged, that is, the resultant force of F1, F3 is 20n, and the direction is opposite to F2. Now the resultant force of the object is the resultant force of F1, F3 (20n) - F2 (16N) = 4N, and the direction is the opposite of F2
RELATED INFORMATIONS
- 1. Three forces, F 1 = 10N, F 2 = 20n, F 3 = 30, with an angle of 120 degrees, are summed
- 2. Given a force F = 100N, decompose it into two forces. Given that the angle between one component F1 and F is 30 degrees, what is the minimum value of the other component F2,
- 3. Two mutually perpendicular forces F1 and F2 act on the same object, making the object move from rest. When the object passes through a period of displacement, F1 does 8j work on the object, F2 does 6J work on the object, then the total work done by F1 and F2 on the object______ J．
- 4. It is known that support a is acted by two forces F1F2, and | F1 | = 40n, which is at an angle with F2 F2 | = 70N, along the horizontal direction; the resultant force of two forces | f | = 100N, calculate the cosine value of angle c tower and the intersection angle beta of resultant force F and F2 Absolute value of vertical index
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- 6. Given that vector x and vector a = (2, - 1) are collinear and satisfy vector a * and vector x = - 18, find vector X
- 7. Simplification of a complex number problem (2-I) ^ 10 / (1-2i) ^ 8=
- 8. Simplify I (2i-1) = () A. -2+iB. 2+iC. -2+iD. -2-i
- 9. -How to simplify 1-2i
- 10. What is the result of simplifying (2 + 3I) (3 + 2I) I (I is an imaginary number)?
- 11. There are three forces F1, F2 and F3 acting on the same point, the magnitude of which is 10N, 20n and 20n respectively A. 0n b.10n c.20n d.30n (double choice)
- 12. If three forces F1, F2 and F3 act on one point, the magnitude of which is 10N, 20n and 20n respectively, and form an angle of 120 degrees with each other, the resultant force is This is a double-choice question: a.0n b.10n c.20n d.30n. I only got a 10N, but I can't think of a second solution,
- 13. In the same horizontal plane, there are three forces acting on a point, which are just balanced. It is known that the included angle of F1 and F2 is 90, the included angle of F2 and F3 is 120, and the ratio of the three forces is 0
- 14. The object is in equilibrium under the action of three common forces. If we know that F1 and F2 are perpendicular, and the angle between F2 and F3 is 120 degrees, then the ratio of the three forces? The object is in equilibrium under the action of three common forces, as shown in Fig. 1-3-10. It is known that F1 and F2 are perpendicular, and the included angle between F2 and F3 is 120 degrees. Then the ratio of the magnitude of the three forces F1 ∶ F2 ∶ F3 is? Please explain, thank you!
- 15. If the vector of1 = (2,2) and the vector of2 (- 2,3) represent two forces F1 and F2 respectively, then the absolute value of F1 + F2 is
- 16. When an object receives three forces, vector F1 = (1,2), vector F2 = (3,6) and resultant force vector f = (1,12), the magnitude of the third force is determined
- 17. F1 and F2 are two horizontal constant forces acting on the object P, with the magnitude of F1 = 3nf2 = 4N, In the process of making the object P move 5 m from static to horizontal, how much work do they do to the object? What is the algebraic sum of their work to the object? How much work do the resultant force of F1 and F2 do to the object? The direction of F1 is vertical downward, and the direction of F2 is horizontal right
- 18. Two objects a and B with the same initial kinetic energy act on a and B respectively with constant force F1 and F2 to make them stop at the same time and compare the size of F1 and F2
- 19. A particle starts to move from rest under the action of two forces F1 and F2 which form an acute angle with each other. If the direction of the two forces remains unchanged, but F1 suddenly increases to F1 If + Δ F, then the particle must move in a constant velocity curve
- 20. When a stationary particle starts to move under the action of two constant forces F1F2 which form an acute angle with each other, and one of the forces is removed after a period of time, the motion of the particle in the two stages before and after removing the force is () A uniformly accelerating linear motion. Uniformly decelerating linear motion B uniformly accelerated linear motion. Uniformly variable speed curvilinear motion C. uniform velocity curve motion. Uniform velocity circular motion D uniformly accelerated linear motion. Uniform circular motion Why B? C.D. circular motion is wrong?