Given that point m (1,2, - 1) is in plane a and a normal vector of plane a is (- 1,1,3), the equation of plane a is obtained
According to the point formula, we can get
The equation of the plane is as follows:
-(x-1)+(y-2)+3(z+1)=0
-x+y+3z+2=0
Namely
x-y-3z=2
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