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Given the plane intercept equation x / A + Y / B + Z / C = 1, how to get the normal vector of the plane directly through the equation without converting it into a general equation
For the plane equation of form ax + by + CZ + D = 0, the normal vector is (a, B, c) x / A + Y / B + Z / C = 1, which is equivalent to X / A + Y / B + Z / C - 1 = 0, then a = 1 / A, B = 1 / B, C = 1 / C, d = - 1, and the normal vector is (1 / A, 1 / B, 1 / C) because if the normal vector is (a, B, c), then
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