Let | vector OA | = | vector ob | = 3, ∠ AOB = 60 °, then | vector OA + vector ob|= By the way!
order
|Vector OA | = | a | = 3, | vector ob | = | B | = 3
Then (| vector OA + vector ob |) ^ 2 = | a + B | ^ 2 = | a | ^ 2 + | B | ^ 2 + 2A * b = 9 + 9 + 2 * 3 * 3 * cos60 ° = 27
Then | vector OA + vector ob | = | a + B | = 3 √ 3
RELATED INFORMATIONS
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- 2. Points a and B (5,0) satisfy the vector OA * vector ob = vector OA * vector Ba, │ vector OA + vector ob = √ 185, and then calculate the a coordinate
- 3. It is known that I is an imaginary unit. In the complex plane, Z1 = 1 + I, Z2 = 2 + 3I correspond to points a and B, O is the origin, and vectors OP, OA and ob satisfy OP = OA + xob, If point P is in the fourth image term Then the value range of X is?
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- 11. What does OA vector multiply ob vector = 0 mean
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- 13. If the vector OA = (3,2) ob = (4,7), then AB =?
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- 15. Why vector Bo vector Ao = vector Ba?
- 16. If the vector OA (x, y), then is the vector Ao (- x, - y) Why?
- 17. Is the coordinate of vector Ao the same as that of vector OA?
- 18. Is negative OA vector equal to Ao vector? Note that OA is negative, not asking if OA is equal to Ao vector!
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