Is the coordinate of vector Ao the same as that of vector OA?

Different
Such as vector a (x1, Y1), B (X2, Y2)
Then the vector AB ((x2-x1), (y2-y1));
Vector BA ((x1-x2), (y1-y2))

RELATED INFORMATIONS

1. If the vector OA (x, y), then is the vector Ao (- x, - y) Why?
2. Why vector Bo vector Ao = vector Ba?
3. AO*BO=AB?
4. If the vector OA = (3,2) ob = (4,7), then AB =?
5. Known vectors OA = (1,3), OB = (2,5) Given the vector OA = (1,3), OB = (2,5), OC = (m, m), if AB is perpendicular to BC, what is the real number m
6. What does OA vector multiply ob vector = 0 mean
7. Let | vector OA | = | vector ob | = 3, ∠ AOB = 60 °, then | vector OA + vector ob|= By the way!
8. Given vector | OA | = 1, | ob | = √ 3, OA * ob = 0, point C is on line ab Given vector | OA | = 1, vector | ob | = √ 3, vector OA * vector ob = 0, point C is on line AB, and angle AOC = 30 °, find (1) vector OA * vector OC (2) let vector OC = MOA + nob, find the value of real numbers m and n
9. Points a and B (5,0) satisfy the vector OA * vector ob = vector OA * vector Ba, │ vector OA + vector ob = √ 185, and then calculate the a coordinate
10. It is known that I is an imaginary unit. In the complex plane, Z1 = 1 + I, Z2 = 2 + 3I correspond to points a and B, O is the origin, and vectors OP, OA and ob satisfy OP = OA + xob, If point P is in the fourth image term Then the value range of X is?
11. Is negative OA vector equal to Ao vector? Note that OA is negative, not asking if OA is equal to Ao vector!
12. In quadrilateral ABCD, if vector AB = vector DC, it must be () a diamond B parallelogram C rectangle D square
13. In quadrilateral ABCD, AB is parallel to CD, ab = CD, AC bisects ∠ bad, and quadrilateral ABCD is diamond?
14. As shown in the figure, in diamond ABCD, the diagonal lines AC and BD intersect at point O. if OA = 4 and ob = 3, the perimeter of diamond ABCD is () A. 5B. 12C. 16D. 20
15. It is known that the diagonal BD of diamond ABCD is 7cm, ∠ a = 60 ° and the perimeter of diamond is__ cm. Then why can't he have a long diagonal of 7? Stupid
16. In the trapezoidal ABCD, the module of AB = the module of 2dc, AC and BD intersect at O. if the module of AB = a, the module of ad = B, then OC =? The answer is one sixth a + one third B I want to know the process
17. If ab → = a →, ad → = B →, then OC →= Ab →, DC →, a →, B → and so on are vectors
18. E1E2 is the unit vector, E1 = 1, E2 = 1 why
19. If the vectors E1 and E2 are two unit vectors with an angle of 60 ° in the plane, a = 2E1 + E2, B = - 3E1 + 2e2, then the angle between a and B is?
20. If E1 and E2 are two vectors which are not collinear, a = E1 + Ke2, B = E2 + Ke1, then a / / B is a necessary and sufficient condition The answer is plus or minus one