In quadrilateral ABCD, AB is parallel to CD, ab = CD, AC bisects ∠ bad, and quadrilateral ABCD is diamond?

Proof: because: in quadrilateral ABCD, AB is parallel to CD, ab = CD, so quadrilateral ABCD is parallelogram,
And because: AC bisects ∠ bad, so: ∠ BAC = ∠ cab = ∠ ACD, so: ad = CD
So: the quadrilateral ABCD is a diamond

RELATED INFORMATIONS

1. In quadrilateral ABCD, if vector AB = vector DC, it must be () a diamond B parallelogram C rectangle D square
2. Is negative OA vector equal to Ao vector? Note that OA is negative, not asking if OA is equal to Ao vector!
3. Is the coordinate of vector Ao the same as that of vector OA?
4. If the vector OA (x, y), then is the vector Ao (- x, - y) Why?
5. Why vector Bo vector Ao = vector Ba?
6. AO*BO=AB?
7. If the vector OA = (3,2) ob = (4,7), then AB =?
8. Known vectors OA = (1,3), OB = (2,5) Given the vector OA = (1,3), OB = (2,5), OC = (m, m), if AB is perpendicular to BC, what is the real number m
9. What does OA vector multiply ob vector = 0 mean
10. Let | vector OA | = | vector ob | = 3, ∠ AOB = 60 °, then | vector OA + vector ob|= By the way!
11. As shown in the figure, in diamond ABCD, the diagonal lines AC and BD intersect at point O. if OA = 4 and ob = 3, the perimeter of diamond ABCD is () A. 5B. 12C. 16D. 20
12. It is known that the diagonal BD of diamond ABCD is 7cm, ∠ a = 60 ° and the perimeter of diamond is__ cm. Then why can't he have a long diagonal of 7? Stupid
13. In the trapezoidal ABCD, the module of AB = the module of 2dc, AC and BD intersect at O. if the module of AB = a, the module of ad = B, then OC =? The answer is one sixth a + one third B I want to know the process
14. If ab → = a →, ad → = B →, then OC →= Ab →, DC →, a →, B → and so on are vectors
15. E1E2 is the unit vector, E1 = 1, E2 = 1 why
16. If the vectors E1 and E2 are two unit vectors with an angle of 60 ° in the plane, a = 2E1 + E2, B = - 3E1 + 2e2, then the angle between a and B is?
17. If E1 and E2 are two vectors which are not collinear, a = E1 + Ke2, B = E2 + Ke1, then a / / B is a necessary and sufficient condition The answer is plus or minus one
18. If vector E1 and E2 are not collinear, vector a = - E1 + Ke2, B = ke1-e2, a is parallel to vector B, and the value of K is obtained
19. When k =?, a = Ke1 + E2, B = E1 + Ke2
20. It is known that | OA | = | ob | = | OC |. The angle between OA, OB and OC is 120 ° and OA + ob + OC (both vectors) is calculated