When k =?, a = Ke1 + E2, B = E1 + Ke2

It's a / / b
Because a / / B, K / 1 = 1 / K, k = ± 1

RELATED INFORMATIONS

1. If vector E1 and E2 are not collinear, vector a = - E1 + Ke2, B = ke1-e2, a is parallel to vector B, and the value of K is obtained
2. If E1 and E2 are two vectors which are not collinear, a = E1 + Ke2, B = E2 + Ke1, then a / / B is a necessary and sufficient condition The answer is plus or minus one
3. If the vectors E1 and E2 are two unit vectors with an angle of 60 ° in the plane, a = 2E1 + E2, B = - 3E1 + 2e2, then the angle between a and B is?
4. E1E2 is the unit vector, E1 = 1, E2 = 1 why
5. If ab → = a →, ad → = B →, then OC →= Ab →, DC →, a →, B → and so on are vectors
6. In the trapezoidal ABCD, the module of AB = the module of 2dc, AC and BD intersect at O. if the module of AB = a, the module of ad = B, then OC =? The answer is one sixth a + one third B I want to know the process
7. It is known that the diagonal BD of diamond ABCD is 7cm, ∠ a = 60 ° and the perimeter of diamond is__ cm. Then why can't he have a long diagonal of 7? Stupid
8. As shown in the figure, in diamond ABCD, the diagonal lines AC and BD intersect at point O. if OA = 4 and ob = 3, the perimeter of diamond ABCD is () A. 5B. 12C. 16D. 20
9. In quadrilateral ABCD, AB is parallel to CD, ab = CD, AC bisects ∠ bad, and quadrilateral ABCD is diamond?
10. In quadrilateral ABCD, if vector AB = vector DC, it must be () a diamond B parallelogram C rectangle D square
11. It is known that | OA | = | ob | = | OC |. The angle between OA, OB and OC is 120 ° and OA + ob + OC (both vectors) is calculated
12. It is known that | vector OA | = | vector ob | = | vector OC |, the angle between vector OA, vector OB and vector OC is 120 ° to find the vector OA + vector ob + vector OC
13. If ABC three points are collinear, what is the relationship between vector OA, vector OB and vector OC
14. Practical application of moment calculation If the power of the reducer is 0.75KW, the output speed is 5R / min, t = 1432.5n. M. that is to say, the output torque of the shaft is 1432.5n. M (if the shaft meets the strength requirements). The reducer is directly connected with the shaft, how to calculate how much weight can be put on the chain conveyor belt with this 1432.5n. M torque?
15. As shown in the figure, the uniform rectangular thin plate with mass m = 1kg and length L = 0.8m is still on the water table, and its right end is flat with the edge of the table. The dynamic friction coefficient between the plate and the table is μ = 0.4. The horizontal force F = 5N is used to push the thin plate to the right to make it turn down the table, and the work done by force F is at least (G is taken as 10m / S2) () A. 1JB. 2JC. 1.6JD. 4J
16. How to calculate the moment? It's more comprehensive
17. Is it necessary to calculate the moment fulcrum without rotation?
18. The calculation of the moment of gear rotation When the cylindrical spur gear rotates, the pitch diameter of the driven wheel d = 30cm, the meshing force F of the driving wheel f = 1kn, the pressure angle a = 20 ° and the transmission moment M. F of the meshing force F to the center of the driven wheel M. f has been solved M. f = M. F1 + M. F2, M. F1 passing through the moment center = 0, then M. f = M. F2 = 1 / 2fcosa = 141n. M, when is this 1 / 2fcosa, and how is this 141 obtained
19. How to calculate the friction moment of rotating shaft? There is mutual pressure between two rotating surfaces, resulting in friction torque. How to calculate this friction torque?
20. Given. Z = (| Z | - 1) + 5I, find the complex Z