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Known vectors OA = (1,3), OB = (2,5) Given the vector OA = (1,3), OB = (2,5), OC = (m, m), if AB is perpendicular to BC, what is the real number m
solution
Because the vector OA = (1,3), OB = (2,5), OC = (m, m)
So vector AB = vector ob - vector OA = (1,2)
Vector BC = vector oc - vector ob = (m-2, m-5)
If AB is perpendicular to BC
Then vector AB * vector BC = (m-2) + 2 (m-5) = 0
So m = 4
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