If the vector OA = (3,2) ob = (4,7), then AB =?
AB = OB-OA
= (1,5)
RELATED INFORMATIONS
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- 3. Let | vector OA | = | vector ob | = 3, ∠ AOB = 60 °, then | vector OA + vector ob|= By the way!
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- 7. In the geometric sense of vector, it is the distance (i.e. length) from the point of the vector on the coordinate plane to the origin / / must be to the origin (0,0)? Must go to the origin (0,0)? From point (4,5) to point (2,2), no?
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- 11. AO*BO=AB?
- 12. Why vector Bo vector Ao = vector Ba?
- 13. If the vector OA (x, y), then is the vector Ao (- x, - y) Why?
- 14. Is the coordinate of vector Ao the same as that of vector OA?
- 15. Is negative OA vector equal to Ao vector? Note that OA is negative, not asking if OA is equal to Ao vector!
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- 17. In quadrilateral ABCD, AB is parallel to CD, ab = CD, AC bisects ∠ bad, and quadrilateral ABCD is diamond?
- 18. As shown in the figure, in diamond ABCD, the diagonal lines AC and BD intersect at point O. if OA = 4 and ob = 3, the perimeter of diamond ABCD is () A. 5B. 12C. 16D. 20
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- 20. In the trapezoidal ABCD, the module of AB = the module of 2dc, AC and BD intersect at O. if the module of AB = a, the module of ad = B, then OC =? The answer is one sixth a + one third B I want to know the process