Given the function FX = loga (x + 1), G (x) = loga (3x), a > 0 and a ≠ 1 (1) If FX + Gx = loga6, find the value of X (2) if FX > GX, find the value range of X
1.x=1
2.x>0
loga(x+1)>loga(3x)
a>1
x+1>3x
0
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