FX is an odd function and GX is an even function FX + Gx = x & # - x, then FX=

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• 1. If the function FX is even, the function GX is odd, and FX + Gx = 2x, then FX = GX=
• 2. The odd function FX and even function GX satisfy the following conditions: FX + Gx = x sub dense of a, - x sub dense of a + 2A > 0 Not equal to 1, if G2 = a find F2
• 3. Given that F X is an odd function, G x is an even function and f (x) - Gx = x2 + 3x + 2, then FX + Gx =?
• 4. FX GX = x ^ 2-x, FX is odd function, GX is even function, find FX
• 5. If f (x) is an even function, G (x) is an odd function, and f (x) + G (x) = x2 + X-2, find the analytic expressions of F (x) and G (x)
• 6. Given the function FX = 2 ^ X and FX = GX + HX, where GX is an odd function and HX is an even function, if the inequality 2A * GX + H (2x) ≥ 0 holds for any x ∈ [1,2], Then the value range of real number a is
• 7. We know that FX = x square + (a + 1) + a square, if FX can be expressed as the sum of an odd function GX and an even function HX (1) Find the analytic expressions of GX and HX. (2) if FX and GX are decreasing functions in the interval (- ∞), (a + 1) square), find the value range of F1
• 8. What are the characteristics of the domains of odd and even functions
• 9. It is known that f (x) is an even function and an increasing function on (0, + ∞) It is known that f (x) is an even function and is an increasing function on (0, + ∞). It is proved that f (x) is an increasing function or a decreasing function on (- ∞, 0)
• 10. Is f (x) = 0 the only function that is both odd and even? Except for other function forms with different domain!
• 11. Given the function f (x) = loga [(a ^ x) - 1], a is greater than 1 1. Find the domain of F (x); 2. Find the value of X that holds f (2x) = f ^ - 1 (x)
• 12. Given the function FX = loga (x + 1) - loga (1-x), a > 0 and a ≠ 1 1. Find the value range of X to make FX > 0
• 13. The function FX = loga (2 + x) - loga (2-x) (a > 0, and a ≠ 1) is known, If 1 is the zero point of y = f (x) - x, judge the monotonicity of F (x) and prove it by definition
• 14. Given the function FX = loga (x + 1), G (x) = loga (3x), a > 0 and a ≠ 1 (1) If FX + Gx = loga6, find the value of X (2) if FX > GX, find the value range of X
• 15. If the definition field and value field pair of function FX = 0.5 (x-1) 2 + a are [1, b] (b > 1), find the value of a and B
• 16. Given that the domain of function FX is (0,2], then the domain of function f √ x + 1?
• 17. It is known that the domain of the function FX is the domain of - 1,1 to find f (x + 2) + F (x + 1)
• 18. Given that the domain of y = FX + 1 is [- 2,3], then the domain of y = f2x-1 is?. why not directly - 2 ≤ x ≤ 3?
• 19. It is known that the domain of definition is R. the function FX satisfies f {a + B} = f {a} * f {B}, and f {x} is greater than 0. What is f {1} = 1 / 2 and f {- 2} equal to?
• 20. The domain of definition of function y = f (x) is R. for any x ∈ R, f (- x) = f (2 + x). When x is less than or equal to 1, FX) = x ^ 2 + 1, find the analytic expression of F (x)