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The function FX = loga (2 + x) - loga (2-x) (a > 0, and a ≠ 1) is known, If 1 is the zero point of y = f (x) - x, judge the monotonicity of F (x) and prove it by definition
A:
f(x)=loga(2+x)-loga(2-x)
The domain satisfies:
2+x>0
2-x>0
So: - 2
RELATED INFORMATIONS
- 1. Given the function FX = loga (x + 1) - loga (1-x), a > 0 and a ≠ 1 1. Find the value range of X to make FX > 0
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- 13. Given that the domain of function FX is (0,2], then the domain of function f √ x + 1?
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- 15. Given that the domain of y = FX + 1 is [- 2,3], then the domain of y = f2x-1 is?. why not directly - 2 ≤ x ≤ 3?
- 16. It is known that the domain of definition is R. the function FX satisfies f {a + B} = f {a} * f {B}, and f {x} is greater than 0. What is f {1} = 1 / 2 and f {- 2} equal to?
- 17. The domain of definition of function y = f (x) is R. for any x ∈ R, f (- x) = f (2 + x). When x is less than or equal to 1, FX) = x ^ 2 + 1, find the analytic expression of F (x)
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