Given that the definition field of function FX is (0, positive infinity) and f (XY) = f (x) + F (y), f (1 / 2) = 1, find f (2) Forget to ask f (4) F8 ()

Let x = 1 / 2, y = 1
That is, f (1 / 2 * 1) = f (1 / 2) = f (1) + F (1 / 2) = 1, f (1) = 0
Let x = 2Y = 1 / 2
That is, f (2 * 1 / 2) = f (2) + F (1 / 2) f (1) = f (2) + F (1 / 2) f (2) = - 1

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