derivatives f（x）=x（e^x -1）-1/2 x^2 The derivative is f'（x）=e^x -1+xe^x-x=（e^x-1）（x+1） And what about the derivative with e?

f（x）=x（e^x -1）-1/2 x^2=xe^x -x-1/2 x^2
f'（x）=x'e^x-x(e^x)'-1-x=e^x-xe^x-1-x
Xe ^ x is a compound function derivative, according to the formula (AB) '= a'B + ab', the derivative of e ^ x is itself, 1 / 2 x ^ 2 and X derivative use (x ^ n) '= NX ^ (n-1)

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