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設x=1/2 y=1 即f(1/2*1)=f(1/2)=f(1)+f(1/2)= 1 f(1)=0 設x=2y=1/2 即f(2*1/2)=f(2)+f(1/2)f(1)=f(2)+f(1/2)f(2)=-1
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