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y=x+1/(x+1) =(x+1)+1/(x+1)-1 令t=x+1(t>2) 則y=t+1/t-1 函數t+1/t(t>2)時遞增(t+1/t是一個很重要的函數,其影像類似於對號,應牢記) 故y>3/2無最小值.
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