Solve the following fractional equation. (1) 1x − 3 = 2 + x3 − X; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; (2) 1x + 1 + 2x − 1 = 4x2 − 1

Solve the following fractional equation. (1) 1x − 3 = 2 + x3 − X; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; (2) 1x + 1 + 2x − 1 = 4x2 − 1

(1) The results show that: 1 = 2x-6-x, x = 7, x = 7 is the solution of the fractional equation; (2) X-1 + 2x + 2 = 4, 3x = 3, x = 1, x = 1 is the increasing root, the fractional equation has no solution