Find the fractional equation x + (1 △ x) = 2 My solution is: X & sup2; + 1 = 2x (both sides are the same as - 2): X & sup2; - 1 = 2x-2 (factorization): (x + 1) (x-1) = 2 (x-1) (about X-1 on both sides): x + 1 = 2 The solution is x = 1 Test, bring in the original equation, X ≠ 0, but the following (x-1) is equal to 0 Now ask if x = 1 is the increasing root of this equation

Find the fractional equation x + (1 △ x) = 2 My solution is: X & sup2; + 1 = 2x (both sides are the same as - 2): X & sup2; - 1 = 2x-2 (factorization): (x + 1) (x-1) = 2 (x-1) (about X-1 on both sides): x + 1 = 2 The solution is x = 1 Test, bring in the original equation, X ≠ 0, but the following (x-1) is equal to 0 Now ask if x = 1 is the increasing root of this equation

: (both sides multiply by x): X & sup2; + 1 = 2x (both sides multiply by - 2): X & sup2; - 1 = 2x-2 (factorization): (x + 1) (x-1) = 2 (x-1) (x + 1) (x-1) - 2 (x-1) = 0 (...)