Find the straight line equation through the intersection of 4x-y-2 = 0 and 3x + 2y-7 = 0, and the angle with the straight line x + 3y-6 = 0 is 45 degrees Thank you. I hope you can hurry up. I'm in a hurry

The intersection of 4x-y-2 = 0 and 3x + 2y-7 = 0 is (1,2)
X + 3y-6 = 0, slope Tan α = - 1 / 3, slope k = Tan (α ± 45 °) = 1 / 2 or - 2
The linear equations: (Y-2) / (x-1) = 1 / 2 and: (Y-2) / (x-1) = - 2
That is: x-2y + 3 = 0. And 2x + y-4 = 0

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