Let (x + 3) square (y + 5) square = R square have and only have one point, and the distance from the line 4x-3y + 2 = 0 is equal to 1, then the radius of the circle R is ()

Let (x + 3) square (y + 5) square = R square have and only have one point, and the distance from the line 4x-3y + 2 = 0 is equal to 1, then the radius of the circle R is ()

If the distance from the center of the circle to the straight line d = 1, then:
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