Let (x + 3) * 2 + (y + 5) * 2 = R * 2 have only one point and the distance from the point to the line 4x-3y + 2 = o be 1, then the radius of the circle R is 1 Change only one point to only two points

The distance from the center of the circle (3, - 5) to the straight line is 5
There are two lines 4x-3y-7 = 0 and 4x-3y + 3 = 0 whose distance is 1 from the line 4x-3y-2 = 0
The distance from the center of the circle to 4x-3y-7 = 0 is 4, and the distance to 4x-3y + 3 = 0 is 6
If the circle intersects with 4x-3y + 3 = 0, then the circle must intersect with 4x-3y-7 = 0, and the number of intersections is more than two, so there are more than two points on the circle whose distance from 4x-3y-2 = 0 is equal to 1, so the circle does not intersect with 4x-3y + 3 = 0
If the distance between the circle and 4x-3y-7 = 0

RELATED INFORMATIONS

1. If there are only two points on the circle C: (x-3) ^ 2 + (y + 5) ^ 2 = R ^ 2 and the distance from the two points to the straight line L: 4x-3y = 17 is 1, what is the value range of R?
2. Point m is on the line y = 2x. If the distance from m to the origin is equal to the distance from m to the line x-2y + 8 = 0, find the coordinates of point M
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