Given P1 (2,5, - 6), find a point P2 on the Y axis so that | p1p2 | = 7

Given P1 (2,5, - 6), find a point P2 on the Y axis so that | p1p2 | = 7

Because P2 is on the Y axis, P2 (0, y, 0)
It should be p1p2 | = 7, so the square of 2 + the square of (5-y) + (- 6) = 7
So y = 2 or y = 8
So P2 (0,2,0) or P2 (0,8,0)