According to the following conditions, find the distance P1 (0, - 2) P2 (3,0) p1 (- 3,1), P2 (2,4) p1 (4, - 2) P2 (1,2)
p1(0,-2)p2(3,0)
P1p2 square = (0-3) square + (- 2-0) square = 9 + 4 = 13
P1p2 = root 13
P1(-3,1),P2(2,4)
P1p2 square = (- 3-2) square + (1-4) square = 25 + 9 = 34
P1p2 = root 34
P1(4,-2)P2(1,2)
P1p2 square = (4-1) square + (- 2-2) square = 9 + 16 = 25
P1P2=5
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