The expression of L1 and L2 is y = 3 / 4x + 3, y = 3 / 4x-3, then the distance between these two parallel lines is

The expression of L1 and L2 is y = 3 / 4x + 3, y = 3 / 4x-3, then the distance between these two parallel lines is

Let y = KX be perpendicular to them, then k * (3 / 4) = - 1K = - 4 / 3Y = - 4 / 3x and the intersection of two parallel lines: y = 3 / 4x + 3Y = - 4 / 3x (- 36 / 25,48 / 25) y = 3 / 4x-3y = - 4 / 3x (36 / 25, - 48 / 25) d = √ [(36 / 25 + 36 / 25) &# 178; + (- 48 / 25-48 / 25) &# 178;] = (1 / 25) √ (72 & # 178; + 96 & # 178;) = (24