Given two points P1 (- 3,5) P2 (5, - 7), the equation of vertical bisector of line p1p2 is obtained Urgent need
The vertical bisector is L
k(P1P2)=(5+7)/(-3-5)=-3/2
k(L)=2/3
The midpoint m of p1p2, then
xM=(-3+5)/2=1,yM=(5-7)/2=-1
L:y+1=(2/3)*(x-1)
Equation of vertical bisector of line p1p2: 2x-3y-5 = 0
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