On the case of the solution of the linear equation with one variable of X: it is reduced to the simplest equation AX = B 1, when a is not equal to 0, there is a unique solution x = B / a 2, when a = 0 and B is not equal to 0 When a = 0, B = 0, any number is the solution of the equation If the equation a (2x + b) = 12x + 5 about X has innumerable solutions, then a = () B equals () process

On the case of the solution of the linear equation with one variable of X: it is reduced to the simplest equation AX = B 1, when a is not equal to 0, there is a unique solution x = B / a 2, when a = 0 and B is not equal to 0 When a = 0, B = 0, any number is the solution of the equation If the equation a (2x + b) = 12x + 5 about X has innumerable solutions, then a = () B equals () process

A (2x + b) = 12x + 5 has many solutions,
That is, 2aX + AB = 12x + 5
(2a-12)x=5-ab
Therefore, 2a-12 = 0,
And: 5-ab = 0
A = 6, B = 5 / a = 5 / 6