m. N is the coefficient, and the difference between MX + 2xy-x and 3x ^ 2-2nxy + 3Y does not contain quadratic term, so the value of m ^ 2-3n can be obtained

m. N is the coefficient, and the difference between MX + 2xy-x and 3x ^ 2-2nxy + 3Y does not contain quadratic term, so the value of m ^ 2-3n can be obtained

There is something wrong with the title itself. Did you copy it wrong? The first polynomial should be MX ^ 2 + 2xy-x, right?
If so:
(mx^2+2xy-x)-(3x^2-2nxy+3y)
=(m-3)x^2+(2-2n)xy-x-3y
Because there is no quadratic term, so:
m-3=0
2-2n=0
The solution is as follows
m=3
n=1
Substituting into the requirements, there are:
m^2-3n
=3^2-3×1
=9-3
=6

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