3. It is proved that the equation x ^ 5-3x = 1 has at least one root between 1 and 2
Certificate: x ^ 5-3x-1 = 0
∵ when x = 1, x ^ 5-3x-1 = - 30
The equation x ^ 5-3x = 1 has at least one root between 1 and 2
RELATED INFORMATIONS
- 1. If the solution of the first order equation x = kx-4 and the equation x-3 = 3x + 1, k =?
- 2. If a root of the quadratic equation x ^ 2-kx-4 = 2 is 2, then the value of K is?
- 3. It is known that the quadratic equation KX ^ + KX + 1 = 0 with respect to X has two equal real roots, then the value of K is___ It is known that the equation x ^ - 2x + k = 0 about X has no real root, then the value range of K is
- 4. What is the value of K when the equation (x ^ 2-4) k-4x ^ 2 + KX + 1 = 0 is a quadratic equation of one variable about x~~
- 5. If the equation KX ^ 3 - (x-1) ^ 2 = 3 (K-2) x ^ 3 + 1 is a quadratic equation of one variable with respect to x, then k =
- 6. (K-3) x ^ (K-2) + x ^ 2 + KX + 1 = 0 is a quadratic equation of one variable about X, then the value of K is Note that it's a quadratic equation of one variable, I think it's 2.3.4, But the teacher said 2 is wrong, thank you very much On the first floor, when you say k = 2, the original formula should be - 1 + x ^ 2 + 2x + 1 = o x ^ 2 + 2x = 0 If the equation has no solution, can't it be a quadratic equation with one variable When x = 2, can (K-3) x ^ (K-2) be regarded as no or - 1
- 7. If the equation (k ^ 2-1) x ^ 2-kx = 3 about X is a quadratic equation of one variable, find K
- 8. It is known that (k ^ 2-1) x ^ 2 + kx-3k + 1 = 0 is a linear equation with one variable. Find the value of K
- 9. Given that KX ^ (2-k) - 5 = 3K is a linear equation of one variable with respect to x, then k =?, the solution of the equation is?
- 10. Given that x = 1 is the solution of the equation K (X-2) / 2-k + 3x / 6 = 4 / 3k, the value of K is obtained It's - (K + 3x) / 6
- 11. It is proved that the equation x ^ 3-3x = 1 has at least one real root in (1,2)
- 12. It is known that the equation 5x-2m = 3x-6m = 1 for X, and the solution of 1 satisfies - 3 < x ≤ 2
- 13. It is known that the solution of the equation 5x-2m = 3x-6m + 1 about X is x, satisfying - 3 < x ≤ 2, and finding the integer value of M
- 14. If the equation of x cube M-1 + 7m = 0 is a linear equation of one variable, what is the value of M? What is the solution of the equation
- 15. If the expansion term of (x + mx-8) (x-3x + n) does not contain X and X terms, we can help to find the value of M and n
- 16. If the expansion of (x + MX + 8) (x-3x + n) does not contain x ^ 3 term and the constant term is 64, find the value of M, n
- 17. (x ^ 2 + MX + n) (x ^ 2-3x + 2) does not contain x ^ 2, X term, find the value of M and n
- 18. If the expansion of (x 2 + m x + 8) (x 2-3 x + n) does not contain x 3 and x 2 terms, the values of M and N are obtained
- 19. m. N is the coefficient, and the difference between MX + 2xy-x and 3x ^ 2-2nxy + 3Y does not contain quadratic term, so the value of m ^ 2-3n can be obtained
- 20. If the equation 2 (x-3) + AX2 = BX about X is a linear equation of one variable, then a and B satisfy () A. A = 0 and B ≠ 0b. A = - 1 and B ≠ 0C. A = 0 and B ≠ 2D. A = 1 and B ≠ 2