If the expansion of (x 2 + m x + 8) (x 2-3 x + n) does not contain x 3 and x 2 terms, the values of M and N are obtained

(x2 + MX + 8) (x2-3x + n) = x4-3x3 + NX2 + mx3-3mx2 + mnx + 8x2-24x + 8N = X4 + (M-3) X3 + (n-3m + 8) x2 + (mn-24) x + 8N. From the result without X3 and X2 terms, M-3 = 0, n-3m + 8 = 0, M = 3, n = 1

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