Given that the quadratic power of a plus a times b equals minus ten, and the quadratic power of B plus a times b equals 14, find the value of a times B

From the meaning of the title, we know that ① A & # 178; + AB = - 10, ② B & # 178; + AB = 14, ① + ② get a & # 178; + 2Ab + B & # 178; = 4 → (a + b) &# 178; = 4 → a + B = ± 2, ① - ② get a & # 178; - B & # 178; = - 24 → (a + b) (a-b) = - 24, if a + B = 2, then A-B = - 12, then a = - 5, B = 7, ab = - 35, if a + B = - 2, then a

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