It is known that the equation (K's Square-1) x's Square-6 (3K-1) x + 72 = 0 has two unequal real roots, so we can find the value of K

It is known that the equation (K's Square-1) x's Square-6 (3K-1) x + 72 = 0 has two unequal real roots, so we can find the value of K

1.k²-1≠0
K ≠ 1 and - 1
two
Δ=36（3k-1）²-4×72×（k²-1）＞0
（3k-1）²-8（k²-1）＞0
9k²-6k＋1-8k²＋8＞0
k²-6k＋9＞0
（k-3）²＞0
As long as K ≠ 3
therefore
The values of K are all the values of K ≠ 1, - 1 and 3

Elden Ring Premiere

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