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1.k²;-1≠0 k≠1且-1 2. Δ=36(3k-1)²;-4×72×(k²;-1)>0 (3k-1)²;-8(k²;-1)>0 9k²;-6k+1-8k²;+8>0 k²;-6k+9>0 (k-3)²;>0 只要k≠3即可 所以 k的值是k≠1,-1且3的所有值.
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