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a^2+b^2+c^2 (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ac)=1+2(ab+bc+ac) 因為(a+b+c)^2>=0最小值為0所以(ab+bc+ac)最小值為-1/2 只有當a=b=c時有最大值3a^2=1 ab+bc+ac=3a^2=1
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