In the arithmetic sequence, if M + n = P, then am + an = AP? In the arithmetic sequence, if M-N = P, then am an = AP?

If M + n = P, then am + an = AP holds, then M-N = P, then am an = AP also holds, because m at this time is equivalent to the previous P. that is to say, these two problems are actually one problem. Then let's see if the proposition am + an = AP holds. Am = a1 + (m-1) × Dan = a1 + (n-1) × DAP = a1 +

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