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如果m+n=p則Am+An=Ap成立,則m-n=p則Am-An=Ap也一定會成立,因為此時的m相當於先前的p.也就是說這兩個問題其實是一個問題.那麼我們看m+n=p則Am+An=Ap這個命題是否成立.Am=A1+(m-1)×dAn=A1+(n-1)×dAp=A1+…
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