If two prime numbers a, B, C and D are different and satisfy the equation a + B = C + D, what is the maximum possible value of a + B?
The largest two prime numbers are: 97, 91, 89, 83, just meeting 97 + 83 = 91 + 89, so the maximum value is 180
RELATED INFORMATIONS
- 1. Given a > b > C, a + B + C = 1, A2 + B2 + C2 = 1, (1) find the range of a + B, (2) find the range of A2 + B2
- 2. Given that A2 + B2 + C2 = 2, t = a-2b-3c, the value range of t can be obtained. If t = 0, the value range of C can be obtained
- 3. Let a, B and C be opposite to each other. If a = π 3 and a = 3, then the value range of B2 + C2 is () A. [3,6]B. [2,8]C. (2,6)D. (3,6]
- 4. Let ABC satisfy a + B + 1 = 1, A2 + B2 + C2 = 1 / 2, then the value range of a is help!
- 5. In the triangle ABC, if a is less than B, less than C and C2 is less than A2 + B2, then the triangle ABC is
- 6. What are the prime numbers of 91
- 7. Prime a × prime B = 91, then, prime a + prime B =?
- 8. 91 =? (prime)
- 9. 57 79 87 49 which is prime
- 10. Given that ABCD is a rational number, the absolute value of (a-b) is less than or equal to 9, the absolute value of (C-D) is less than or equal to 16, and the absolute value of (a-b - + D) is 25, find the absolute value of (- a)
- 11. If four two digit prime numbers a, B, C and D are different and satisfy the equation a + B = C + D, then what is the minimum possible value of (1) a + B? (2) What is the maximum possible value of a + B?
- 12. Find all prime numbers P such that p * (p-1 power-1 of 2) is the K power of a positive integer, k > 1 and K is a positive integer
- 13. For four digit. ABCD, if there is a prime number P and a positive integer k, such that: a × B × C × d = PK, and: a + B + C + D = PP-5. Find the minimum value of such four digit and explain the reason
- 14. The sum of three consecutive natural numbers is 99, the largest of which is ()
- 15. Four natural numbers of ABCD multiplied by four are equal to DCBA. What are the ABCD numbers
- 16. It is known that a, B, C and D are prime numbers (a, B, C and D are allowed to be the same), and a * b * c * D is the sum of 55 continuous natural numbers. Find the minimum value of a + B + C + D
- 17. Given that a, B, C and D are prime numbers and that a × B × C × D is the sum of 77 nonzero continuous natural numbers, what is the minimum value of a + B + C + D?
- 18. Given that a, B, C and D are prime numbers and that a × B × C × D is the sum of 77 nonzero continuous natural numbers, what is the minimum value of a + B + C + D?
- 19. Given that a, B and C are prime numbers and a = B + C, what is the minimum value of a × B × C?
- 20. If A-B = B-C = 20, then 3A + 2B + C =? Analytically, if A-B = B-C = 20 and a-c = 40, then A-B, B-C and a-c are not multiples of 3, that is, a, B and C have a number that is multiples of 3. Why?