For four digit. ABCD, if there is a prime number P and a positive integer k, such that: a × B × C × d = PK, and: a + B + C + D = PP-5. Find the minimum value of such four digit and explain the reason

In order to minimize the value of a + B + C + D = PP-5, P should be the minimum. Obviously, when p = 2, it is not required, otherwise 22-5 is negative, so the minimum value of P is 3. At this time, a + B + C + D = PP-5 = 22, a × B × C × d = 3K. To make the minimum value of four digits, a at the highest position, the minimum value is: a = 1, then B + C + D = 22-1 = 21, and because it is 3k, it must be

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