It is known that a, B, C and D are prime numbers (a, B, C and D are allowed to be the same), and a * b * c * D is the sum of 55 continuous natural numbers. Find the minimum value of a + B + C + D

If a * b * c * D is the sum of 55 nonzero continuous natural numbers, there must be a factor of 55
Let the first continuous natural number be X
a*b*c*d=(x+x+54)x55/2
=(x+27)x5x11
When x = 2, x + 27 has the minimum prime 29
The minimum value of a + B + C + D is 2 + 5 + 11 + 29 = 47

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