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a*b*c*d是55個非零連續自然數之和,則其中必有55的因數. 設連續自然數第一個為x a*b*c*d=(x+x+54)x55/2 =(x+27)x5x11 x=2時,x+27有最小質數29 a+b+c+d的最小值是2+5+11+29=47
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