In parallelogram ABCD, de bisects AB vertically, the perpendicular foot is point E, the perimeter of parallelogram ABCD is 36cm, and the perimeter of triangle abd is 10cm less than that of parallelogram ABCD. The length of AB and BC can be calculated Urgent need

In parallelogram ABCD, de bisects AB vertically, the perpendicular foot is point E, the perimeter of parallelogram ABCD is 36cm, and the perimeter of triangle abd is 10cm less than that of parallelogram ABCD. The length of AB and BC can be calculated Urgent need

It is known from the meaning of the title that de bisects AB vertically and the perpendicular foot is the point E, so the triangle abd is an isosceles triangle
Because the perimeter of parallelogram ABCD is 10 cm less than that of parallelogram ABCD
So the circumference of the triangle abd is 26cm
It is known that the triangle abd is an isosceles triangle, so ad = BD
It is known that in the parallelogram ABCD, ad = BC, DC = ab
So AB = DB = BC, the perimeter of parallelogram ABCD is equal to the perimeter of triangle abd plus the length of side DC
So AB = DC = 36-26 = 10
bc=ad=（26-10）/2=8