In the parallelogram ABCD, ad = 2ad, M is the midpoint of AB, connecting DM and MC. What is the positional relationship between DM and MC? Please prove AB=2AD Revision of the previous question

In the parallelogram ABCD, ad = 2ad, M is the midpoint of AB, connecting DM and MC. What is the positional relationship between DM and MC? Please prove AB=2AD Revision of the previous question

It is proved that because the sum of the internal angles of the triangle is 180 degrees, the sum of the internal angles of the triangle AMD and the triangle BMC is 360 degrees. Because the quadrilateral ABCD is a parallelogram, the angle a plus the angle B equals 180 degrees. So the angle ADM plus amd plus BMC plus BCM equals 180 degrees. Because m is the midpoint of AB, am equals BM and ad equals BC