Let X and y be the two real roots of the equation m2-2am + A + 6 = 0, then the minimum value of (x-1) 2 + (Y-1) 2 is () A. -1214B. 18C. 8D. 34

Then (x-1) 2 + (Y-1) 2 = x2 + y2-2 (x + y) + 2 = (x + y) 2-2xy-2 (x + y) + 2 = (2a) 2-2 (a + 6) - 4A + 2 = 4a2-6a-10 = 4 (a-34) 2-494

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