If the quadratic equations 3x-7 = 0, 2x + 3y-1 = 0 and 2x + y-m = 0 have common solutions, then the value of? Is?
3x-7=0
x=7/3
Substituting x = 7 / 3 into 2x + 3y-1 = 0
So 14 / 3 + 3y-1 = 0
3y+11/3=0
y=-11/9
Substituting x = 7 / 3, y = - 11 / 9 into 2x + y-m = 0
We get 14 / 3-11 / 9 + M = 0
m=-31/9
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